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Post by jasonandsarah on Apr 22, 2014 12:48:35 GMT -5
They both work and appear to have the same drivers and inner workings?
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Post by jasonandsarah on Apr 22, 2014 12:57:28 GMT -5
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Post by Pokahpolice on Apr 22, 2014 12:58:43 GMT -5
One is a resistor and the other is a SMT solder pad. PWM = pulse width modulation PWM in a nutshell is a better more specific way to drive the LEDs to achieve their optimal performance. They run cooler, use less energy, and produce more PUR. This post is confusing. The resistor and solder pad have noting to do with PWM. |
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Post by Pokahpolice on Apr 22, 2014 13:04:25 GMT -5
Your fixture isn't Apex ready. Analog dims an LED by using an variable resistor to control the amount of DC current going to the lights. In your case a dimmer knob. The APEX needs to be wired into each individual circuit so it can now take the place of the variable resistor. It's not an easy task that someone can walk you through. You need to understand the wiring of the fixture and the wiring/programing of the Apex. |
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Post by BriMc on Apr 22, 2014 13:06:15 GMT -5
Sorry Bruce I was replying to two different posts
The "One is a resistor and the other is a SMT solder pad" was to Jason's post and the rest was explaining PWM
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Post by jasonandsarah on Apr 22, 2014 13:09:56 GMT -5
I just signed up for the Neptune systems forum and they have a very informative diy section with all the info I'll ever need I think. Ty guys very much for the info and help
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Post by moulton712 on Apr 22, 2014 23:12:35 GMT -5
Ok so my question is why does one look like a transistor and the other is just metal? Are they possibly upside down? One set is on the front where you can see them and on the other it's on the inside of the plate? Sorry dumb auto correct! I fixed all the misspells The boards are generic boards. They probably made a million of them. You need a resistor for every three diodes in series (analog) The difference is the layout and design of the whole light. I bet there are resistors in there but the path the wires take are different. Resistors step down the voltage from high to a lower voltage. If no resistance or too much voltage the you would fry the diode. I use diodes at my shop all the time. Especially putting in remote starters. I hope that helps. |
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Post by jasonandsarah on Apr 23, 2014 5:07:26 GMT -5
They are offering to send me yet another light so witch one is better? They said I can choose witch one I want and they'll send me the matching one?
From what I was told yesterday it sounded like the one without showing capacitors was better, but moulton made it sound like the one with the capacitors is better? Once again I'm confused haha
Maybe I should sell all the lights and just upgrade to better lights?
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Post by jasonandsarah on Apr 23, 2014 6:26:06 GMT -5
Someone with electrical experience must be awake? I need to finish dealing with this company before they close!  It's so much harder to consistently communicate with the Chinese companies because of the extreme time differences. |
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Post by moulton712 on Apr 23, 2014 10:30:53 GMT -5
There is no better, just different. Well none of us would have the tools to see the very small differences in how each work from an efficiency standpoint
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Post by jasonandsarah on Apr 23, 2014 10:36:23 GMT -5
I opened it up there's no resistors anywhere on the board at all? One light seems brighter then the other on the same setting? Why is this?
Could I just instal resistors in the same fashion they did? They can't be very expensive.
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Post by BriMc on Apr 23, 2014 11:39:33 GMT -5
As I stated before it was a process change in the manufacturing. The fixture with all the resistors on it may have been a newer or older design. One way they have what are called power traces on the board which feed the resistors power lets say the power on these traces are 3 watts in turn the each resistor lowers the power to each LED to 2.2 wars max. I would think this would be the best design.
The fixture without any resistors on it could either have one resistor placed someplace else in the circuit delivering 2.2 watts(or more) to the board, or they had the transformers made to supply the needed 2.2 watts. Either way they will both work the but the latter of the two would be cost saving.
To answer your question yes it is easy and very inexpensive but no, adding resistors wouldn't accomplish anything, the power is all ready where it needs to be.
Techies don't roast me I know resistors are measured in Ohms, I used watts to keep it simple.
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Post by jasonandsarah on Apr 23, 2014 12:01:25 GMT -5
Techies don't roast me I know resistors are measured in Ohms, I used watts to keep it simple. I appreciate you keeping it simple! ;D |
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Post by jasonandsarah on Apr 23, 2014 12:02:17 GMT -5
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Post by jasonandsarah on Apr 23, 2014 12:03:21 GMT -5
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It's so much harder to consistently communicate with the Chinese companies because of the extreme time differences.
